For questions 1 and 2, use integer values of from - 3 to 3 to graph the equation.

1) y = - 2x2 + 3

Question

Trenton

Mathematics

16 April, 13:14

For questions 1 and 2, use integer values of from - 3 to 3 to graph the equation.

1) y = - 2x2 + 3

+1

Answers (1)

Know the Answer?

Holmes · Answer 1

1) y=-2x²+3 Therefore making a parabola

x - 3 - 2 - 1 0 1 2 3

y - 15 - 5 1 3 1 5 15

2) y=1/3|x|-2

x - 3 - 2 - 1 0 1 2 3

y - 1 - 1.3 - 1.6 - 2 - 1.6 - 1.3 - 1

For questions 1 and 2, use integer values of from - 3 to 3 to graph the equation.1) y = - 2x2 + 3

For questions 1 and 2, use integer values of from - 3 to 3 to graph the equation.

1) y = - 2x2 + 3