A circular above ground pool has a height of 52 inches, and a volume of 1100 ft^3. What is the radius of the pool to the nearest tenth of a foot? Use the equation V=pi*r^2*h.

(V = volume, r = radius, and h=height)

9.0 ft

Step-by-step explanation:

Height = 52/12 ft = 13/3 ft

1100 = 3.14 * r² * 13/3

r² = 80.84272415

r = 8.991258208

9 ft

Step-by-step explanation:

The pool is in the shape of a cylinder

V = pi r^2h

We need to change the height from inches to ft

52 inches * 1ft/12 inches = 13/3 ft

1100 = pi * r^2 * 13/3

Multiply each side by 3

3300 = pi * r^2 * 13/3 * 3

3300 = pi * r^2 * 13

Divide each side by 13pi

3300/13pi = pi * r^2 * 13/13pi

3300 / (13*3.14) = r^2

80.84272415 = r^2

Take the square root of each side

sqrt (80.84272415) = sqrt (r^2)

8.991258208 = r

To the nearest foot

9 = r