Consider the graph of the following quadratic equation. y=-x^2-10x+24 What is the y value of the vertex?

In standard form, y=Ax^2+Bx+C, you can't read the vertex easily, so you can complete the square to get vertex form, y=a (x-h) ^2 + k where (h, k) is the vertex ...

This equation can be changed to

x^2-10x+25-25+24

(x-5) ^2-1

Therefore, the vertex is (5,-1)