There are three consecutive even integers. If twice the first integer added to the second is 268, 244 find all three integers.

Question

Fletcher Griffith

Mathematics

23 January, 13:31

There are three consecutive even integers. If twice the first integer added to the second is 268, 244 find all three integers.

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Answers (1)

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Lillian Gallegos · Answer 1

The numbers would be 89,414, 89,416, and 89,418

Step-by-step explanation:

In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.

2 (x) + x + 2 = 268,244

3x + 2 = 268,244

3x = 268,242

x = 89,414

Since the first number is 89,414, we know the next two are 89,416 and 89,418.