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15 August, 18:20

What are the x-intercepts of y = (x - 2) (x + 5) ?

(0, 2) and (0, - 5)

(0, - 2) and (0, 5)

(-2, 0) and (5, 0)

(2, 0) and (-5, 0)

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Answers (1)
  1. 15 August, 18:41
    0
    Step-by-step explanation:

    x-intercepts exist when y = 0. Set the quadratic equal to 0 and solve each expression for x:

    0 = (x - 2) (x + 5)

    By the Zero Product Property, either x - 2 = 0 or x + 5 = 0 (because when you multiply 0 by anything, you get a 0. Which means that one of these expressions has to equal 0.)

    x - 2 = 0 so

    x = 2

    x + 5 = 0 so

    x = - 5

    Again, the x-intercept exists when y = 0, so the number for y in the coordinates will be 0's. (2, 0) and (-5, 0) are your coordinates.
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