Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln (2).

Question

Stanley Burns

Mathematics

28 November, 16:54

Find the area of the surface generated by revolving the curve x = (e^y + e^-y) / 2 from x = 0 to x = ln (2).

+2

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Aydan Blanchard · Answer 1

Here's the calculation of area

π [ ln 2 + 1 / 2 sinh (2 ln 2) ]=π [ln 2 + 1 4 (2^2 - 2 ^-2) ]

=π [ln 2 + 1 / 4 (4 - 1 / 4) ]=π (ln 2 + 15 / 16) ≈ 5.122