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29 October, 15:59

A particle moves along the x-axis so that at any time t, measured in seconds, its position is given by s (t) = sin (t) - 4cos (2t), measured in feet. What is the acceleration of the particle at time t = π seconds?

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  1. 29 October, 16:01
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    16 ft/s²

    Step-by-step explanation:

    s (t) = sin (t) - 4cos (2t)

    Differentiation for v

    v (t) = cos (t) + 8sin (2t)

    Differentiate for a

    a (t) = - sin (t) + 16cos (2t)

    At t = π

    a (π) = - sin (π) + 16cos (2π)

    = 0 + 16

    = 16
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