The length of a rectangle is twice the width. the perimeter is 36feet. find the length time width

Let the length of the rectangle be L and the width be W.

Given that the length is twice the width, Then:

L = 2W ... (1)

But we know that the perimeter is 36.

==> 2L + 2W = 36

==> 2L + L = 36

==> 3L = 36

==> L = 36/3 = 12

==> W = 12/2 = 6

Now we will calculate the area:

==> A = L * W = 12 * 6 = 72 square feet.

Then the area of the rectangle is 72 square feet.

What do you know?: The Length Is Twice the Width

Write an equation: l = 2w

What else do you know?: The Perimeter is 36

Write and equation: P = 2l + 2w >>> 36 = 2l + 2w

Divide 36 by 3: 36 / 3 = 12

Put 12 in for w: l = 2 (12) >>> l = 24

The Length is 24, and the Width is 12.