F (x) = x4/5 (x - 6) 2 find the critical numbers of the function

You can find the critical numbers by finding the derivative of the function and solving for 0.

F (x) = x (4/5) (x-6) (2) = x (8/5) (x-6) = (8/5) (x^2 - 6x)

Taking the derivative:

F' (x) = (8/5) (2x - 6)

F' (x) = 0 at x = 3,

critical number = 3