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11 November, 05:26

In △ABC, m∠A=53°, m∠B=17°, and a=27. Find the perimeter of the triangle.

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  1. 11 November, 05:40
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    Using the Law of Sines (sinA/a=sinB/b=sinC/c) and the fact that all triangles have a sum of 180° for their angles.

    The third angle is C is 180-53-17=110°

    27/sin53=b/sin17=c/sin110

    b=27sin17/sin53, c=27sin110/sin53

    And the perimeter is a+b+c so

    p=27+27sin17/sin53+27sin110/sin53 units

    p≈68.65 units (to nearest hundredth of a unit)
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