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12 December, 06:03

Find the domain of the function. (Enter your answer using interval notation.)

f (x) = x+3/x^2-1

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  1. 12 December, 06:27
    0
    The domain is:

    In interval notation:

    (-infinity,-1) U (-1,1) U (1, infinity)

    In inequality notation: x<-1 or or - 1
    The problem:

    Find the domain of f (x) = (x+3) / (x^2-1)

    Step-by-step explanation:

    The only thing that needs worrying here is the fraction since you can't divide by 0.

    So if we solve x^2-1=0 we will find what x cannot be and everything else will be in the domain of the function.

    Lets solve:

    x^2-1=0

    Add 1 on both sides:

    x^2=1

    Take square root of both sides:

    x=1,-1

    So the domain is all real numbers except x=-1, x=1.

    The domain is:

    In interval notation:

    (-infinity,-1) U (-1,1) U (1, infinity)

    In inequality notation: x<-1 or - 1
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