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27 May, 16:55

Find the remainder for (b3 - 5b2 - 2b + 8) ⎟ (b - 4).

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  1. 27 May, 17:10
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    (b^3-5b^2-2b+8) / ((b-4)

    (b^2) (b^3-5b^2-2b+8-b^3+4b^2)

    (b^2) (-1b^2-2b+8)

    (b^2-b) (-1b^2-2b+8+b^2-4b)

    (b^2-b) (-6b+8)

    (b^2-b-6) (-6b+8+6b-24)

    (b^2-b-6) (-16)

    Remainder=-16
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