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9 March, 10:46

If 2x^2+5x-12 = (2x-3) (x+4) which equations should be solved to find the roots of 2x^2+5x-12=0

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  1. 9 March, 11:12
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    The equation should be solved to find the roots of 2x² + 5x - 12 = 0 is

    (2x - 3) (x + 4) = 0

    Step-by-step explanation:

    The roots of an equation is values of x when y is equal to zero

    ∵ y = 2x² + 5x - 12 is a quadratic equation

    ∴ The roots of the equations are values of x when y = 0

    ∵ The factorization of 2x² + 5x - 12 is (2x - 3) (x + 4)

    ∵ 2x² + 5x - 12 = (2x - 3) (x + 4)

    ∵ 2x² + 5x - 12 = 0

    - Equate the right hand side above by 0

    ∴ (2x - 3) (x + 4) = 0

    - Now equate each bracket by 0 to find the values of x

    ∵ 2x - 3 = 0

    - Add 3 to both sides

    ∴ 2x = 3

    - Divide both sides by 2

    ∴ x = 1.5

    ∵ x + 4 = 0

    - Subtract 4 from both sides

    ∴ x = - 4

    ∴ The roots of the equations are - 4 and 1.5

    The equation should be solved to find the roots of 2x² + 5x - 12 = 0 is

    (2x - 3) (x + 4) = 0
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