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30 November, 23:12

Given a square with two vertices of one side located at - 5,-3 and - 5,12 in square units what is its area

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  1. 30 November, 23:18
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    225 units squared

    Step-by-step explanation:

    Lets find the distance (the side length of the square)

    D=sqrt ((x2-x1) ^ (2) + (y2-y1) ^ (2))

    plug in the coordinates:

    D=sqrt ((-5 - (-5)) ^ (2) + (12 - (-3)) ^ (2))

    D=sqrt (0^ (2) + 15^ (2))

    D=sqrt (15^ (2))

    D=15

    Area of a square is side length squared

    A=s^2

    A=15^2

    A=225 units squared
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