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1 April, 18:40

Find all solutions for a triangle with a=26, b=29, and A=58

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  1. 1 April, 18:41
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    a=26

    b=29

    A=58 degrees

    Using the Law of sines we can fine angle B:

    (sin A) / a = (sin B) / b multiply both sides by b

    sin B = (sin A) (b / a)

    sin B = (sin 58) (29/26)

    sin B = 0.9458997995

    B = arcsin 0.9458997995

    B = 71 degrees approximately

    C = 180 - (A + B)

    C = 180 - (58 + 71)

    C = 51 degrees

    (sin A) / a = (sin C) / c

    c = a ((sin C) / (sin A))

    c = 26 (sin (51) / sin (58))

    c = 23.83
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