Two pools are being filled with water. To start, the first pool contains 567 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.25 liters per minute. Water is being added to the second pool at a rate of 40.5 liters per minute.

After how many minutes will the two pools have the same amount of water?

How much water will be in each pool when they have the same amount?

Question

Rudy Molina

Mathematics

27 December, 12:27

Two pools are being filled with water. To start, the first pool contains 567 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.25 liters per minute. Water is being added to the second pool at a rate of 40.5 liters per minute.

After how many minutes will the two pools have the same amount of water?

How much water will be in each pool when they have the same amount?

+5

Answers (1)

Know the Answer?

Jakob Hobbs · Answer 1

Let the volume when they are equal in both tanks = V liters and the time taken

to reach this volume = t minutes.

first tank: - V = 20.25t + 567

second tank: V = 40.5t

solving: first subtract : -

0 = - 20.25t + 567

20.25t = 567

t = 567/20.25 = 28 minutes Answer

Volume of water at this time = 40.5 * 28 = 1134 liters Answer