Find the constant c such that the denominator will divide evenly into the numerator

x^5-2X^2+x+c / X+2

Question

Saige Norris

Mathematics

17 July, 19:49

Find the constant c such that the denominator will divide evenly into the numerator

x^5-2X^2+x+c / X+2

+1

Answers (2)

Know the Answer?

Noe · Answer 1

If f (x) = x^5 - 2 x^2 + x + c is divisible by : x + 2

then : f ( - 2) = 0

f ( - 2) = ( - 2) ^5 - 2 ( - 2) ^2 + ( - 2) + c = 0

- 32 - 8 - 2 + c = 0

c = 32 + 8 + 2

Answer:

c = 42

Austin Sherman · Answer 2

Let f (x) = x^5 - 2x^2 + x + c

For the denominator to divide numerator, then

f (-2) = 0

(-2) ^5 - 2 (-2) ^2 - 2 + c = 0

-32 - 2 (4) - 2 + c = 0

-32 - 8 - 2 + c = 0

-42 + c = 0

c = 42.

The constant c = 42.

Find the constant c such that the denominator will divide evenly into the numeratorx^5-2X^2+x+c / X+2

Find the constant c such that the denominator will divide evenly into the numerator

x^5-2X^2+x+c / X+2