Determine the number of zeros of the polynomial function. h (t) = (t - 6) 2 - (t + 6) 2

Step-by-step explanation:

(t - 6) ^2 = t^2 - 12t + 36

(t + 6) ^2 = t^2 + 12t + 36

(t - 6) ^2 - (t + 6) = t^2 - 12t + 36 - (t^2 + 12t + 36)

(t - 6) ^2 - (t + 6) = t^2 - 12t + 36 - t^2 - 12t - 36

(t - 6) ^2 - (t + 6) = - 24t The other 4 terms cancel out.

-24t = 0 Divide by - 24

t = 0

There is one root.