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3 December, 12:10

Find the roots of the polynomial equation x^3+2x^2+3x+6=0

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  1. 3 December, 12:13
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    Answer: x=-2

    Step-by-step explanation:

    x^3+2x^2+3x+6=0

    (x+2) (x^2+3) = 0

    x+2=0 or x^2+3=0

    x=-2
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