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Sharon Avery
Mathematics
23 November, 05:08
Solve 20x + 12 ≥ 14x + 30
A. x ≥ 3
B. x ≤ 7
C. x ≤ 3
D. x ≥ 7
+1
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1
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Gunner Fernandez
23 November, 05:27
0
20x+12≥14x+30 subtract 12 from both sides
20x≥14x+18 subtract 14x from both sides
6x≥18 divide both sides by 6
x≥3
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