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30 January, 04:54

Y = 1/3x+3

Y=2x-2

How can I solve of systems of equation substitution.?

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Answers (2)
  1. 30 January, 04:58
    0
    x=3

    Step-by-step explanation:

    1/3x+3 = 2x-2

    Then solve for x:

    1/3x-2x=-2-3

    1/3x-6/3x=-5

    -5/3x=-5

    -5x=-5*3

    -5x=-15

    x=-15/-5

    x=3
  2. 30 January, 05:20
    0
    x=3

    Step-by-step explanation:

    Since both equations solve for y, set the equations equal to each other:

    1/3x+3 = 2x-2

    Then solve for x:

    1/3x-2x=-2-3

    1/3x-6/3x=-5

    -5/3x=-5

    -5x=-5*3

    -5x=-15

    x=-15/-5

    x=3
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