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26 September, 17:50

Y = x2-3x-4 x=y+8

solution set

a: { (-1,0), (4,0) }

b: { (8,0), (0,8) }

c: { (0,0) }

d: { (2,-6) }

e: there is no real solution

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Answers (1)
  1. 26 September, 18:08
    0
    Plug in x into first equation

    Y = (y+8) ^2-3 (y+8) - 4

    Y=y2+16y+64-3y-24-4

    Y=y2+13y+36

    Y = (y+9) (y+4)

    Y = - 9,-4 plug in - 9 to find x n plug in - 4 to find its x

    X=y+8

    X=-9+8 x=-1 Plug in - 1 into first equation

    Y=x2-3x-4

    Y=-1^2+3-4

    Y = 1+3-4

    Y=0

    (-1,0) do the same for - 4

    X=y+8

    X=-4+8

    X=4

    Y=x2-3x-4

    Y=4^2-12-4

    Y=16-16

    Y=0

    (4,0)

    Solutions are (-1,0) (4,0)
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