66.7% of men and 50.8% of women in the U. S. Were overweight. Given that 48.7% of american are men and 51.3% are women, find the probability that a randomly selected American is an overweight man

Question

Rudy Molina

Mathematics

16 January, 06:27

66.7% of men and 50.8% of women in the U. S. Were overweight. Given that 48.7% of american are men and 51.3% are women, find the probability that a randomly selected American is an overweight man

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Answers (2)

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Selena Hayes · Answer 1

Answer: 0.325 or 32.5% Step-by-step explanation: From the question it says that 66.7% of american men are overweight and 50.8% of their women are also overweight. AND 48.7% of their population are men and 51.3% are women. The probability that a randomly selected american is an overweight man will be: Well, first and foremost, we have to find the probability of selecting a man: 48.7/100 = 0.487 Therefore, the probability of the mam selected been an overweight man will be 0.487*0.667 = 0.325*100 = 32.5%

Marcos Cook · Answer 2

32.48%

Step-by-step explanation:

We have the percentage of americans that are men, and we have the percentage of men that are overweight, so to find the percentage of americans that are overweight men, we just need to multiply both percentages:

If 48.7% of americans are men, and 66.7% of these men are overweight, then 48.7% * 66.7% of americans are men that are overweight:

48.7% * 66.7% = 32.48%

So, the probability of a ramdomly selected american being an overweight man is 32.48%