Given that p varies directly as the square of q and p equal 12 when q equal 3 find the value of p when q equal 5

Question

Simeon

Mathematics

6 November, 09:08

Given that p varies directly as the square of q and p equal 12 when q equal 3 find the value of p when q equal 5

+3

Answers (1)

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Frauline · Answer 1

p = 100/3

Step-by-step explanation:

P varies directly as q^2 and

p = k q^2

We know p = 12 and q = 3, we can solve for k

12 = k 3^2

12 = k*9

Divide by 9

12/9 = k

4/3 = k

p = 4/3 q^2

When q = 5

p = 4/3 * 5^2

p = 4/3*25

p = 100/3