Ask Question
27 February, 04:45

Identify the center and radius for the equation x ^ 2 + (y - 3) ^ 2 = 4

+1
Answers (1)
  1. 27 February, 05:01
    0
    r = 2. The center is at (0, 3).

    Step-by-step explanation:

    Compare the given x ^ 2 + (y - 3) ^ 2 = 4 to the standard equation

    (x - h) ^2 + (y - k) ^2 = r^2.

    It becomes obvious that h = 0, k = 3 and r = 2. The center is at (0, 3).
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Identify the center and radius for the equation x ^ 2 + (y - 3) ^ 2 = 4 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers