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27 October, 02:25

What is f (x) / g (x) when f (x) = - 2x^3+x^2+16x-15 and g (x) = x+3?

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  1. 27 October, 02:39
    0
    Hello,

    if x≠-3

    f (-3) = - 2 (-3) ^3 + (-3) ²+16 (-3) - 15=-2 * (-27) + 9-48-15=54+9-48-15=0

    f (x) / g (x) = (-2x^3+x²+16x-15) / (x+3) = (x+3) * (-2x²+7x-5) / (x+3) = - 2x²+7x-5
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