Complete the square and graph: 4y^2+x+8y+1=0

The answer to your question is:

Step-by-step explanation:

4y² + x + 8y + 1 = 0

4y² + 8y = - x - 1

4 (y² + 8y) = - x - 1

(y² + 2y) = - 1/4 x - 1/4

(y² + 2y + 1) = - 1/4 x - 1/4 + 1

(y² + 2y + 1) = - 1/4 x + 3/4

(y + 1) ² = - 1/4 (x - 3)

Vertix (3, - 1)

It's a parabola that opens to the left.