The first two steps in determining the solution set of the system of equations, y = x2 - 6x + 12 and y = 2x - 4, algebraically are shown in the table. Which represents the solution (s) of this system of equations? (4, 4) (-4, - 12) (4, 4) and (-4, 12) (-4, 4) and (4, 12)

Question

Jadon Simmons

Mathematics

3 June, 05:46

The first two steps in determining the solution set of the system of equations, y = x2 - 6x + 12 and y = 2x - 4, algebraically are shown in the table. Which represents the solution (s) of this system of equations? (4, 4) (-4, - 12) (4, 4) and (-4, 12) (-4, 4) and (4, 12)

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Answers (1)

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Jamison Rose · Answer 1

Y = 2x - 4 ... so sub in 2x - 4 for x in the other equation

y = x^2 - 6x + 12

2x - 4 = x^2 - 6x + 12

x^2 - 6x - 2x + 12 + 4 = 0

x^2 - 8x + 16 = 0

(x - 4) (x - 4) = 0

x - 4 = 0

x = 4

x - 4 = 0

x = 4

solution is (4,4)