What are the solutions of the equation (x-3) ^2 + 2 (x-3) - 8 = 0

Question

Lee

Mathematics

26 May, 22:14

What are the solutions of the equation (x-3) ^2 + 2 (x-3) - 8 = 0

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Answers (2)

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Watson · Answer 1

Hello,

(x-3) ²+2 (x-3) - 8=0

x²-6x+9+2x-6-8=0

x²-4x-5=0

∆=b²-4ac = (4) ²-4 (-5) (1) = 16+20=36

x₁,₂=-b±√∆/2a=4±6/2

x₁=4-6/2=-2/2=-1

x₂=4+6/2=10/2=5

Therefore the solutions are

x=-1 and x=5

See you soon : - )

Knox · Answer 2

Expand and simplify

(x-3) (x-3) + 2 (x-3) - 8=0

(x-3+2) (x-3) - 8=0

(x-1) (x-3) - 8=0

x^2 - 4x + 3-8=0

x^2 - 4x - 5=0

x^2 - 5x + x-5=0

x (x-5) + x-5=0

(x+1) (x-5) = 0

x = - 1, 5