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27 July, 12:41

Find the first three iterates of the function f (z) = 2z + (3 - 2i) with an initial value of

z0 = - 1 - 2i.

a.

1 - 6i, 5 - 14i, 13 - 30i

c.

5 - 2i, 13 - 2i, 29 - 2i

b.

2 - 5i, 9 - 17i, 21 - 37i

d.

3 - 2i, 17 - 2i, 23 - 2i

+3
Answers (1)
  1. 27 July, 12:46
    0
    5 - 2i, 13 - 2i, 29 - 2i iam not sure though if anyone does know the real answer you can put it in the comment
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