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Mathematics
24 July, 07:20
Solve y-2x=1, 3x-4y=1 using substitution m
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Ahmad Knox
24 July, 07:22
0
Step-by-step explanation:
given
y - 2x = 1
y = 1 + 2x ... equation 1
3x - 4y = 1 ... equation 2
Now putting y = 1 + 2x in equation 2
3x - 4 (1 + 2x) = 1
3x - 4 - 8x = 1
- 5x = 1 + 4
- 5x = 5
Therefore x = - 1
Now putting x = - 1 in equation 1
y = 1 + 2 * (-1)
= 1 - 2
= - 1
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Mohammad
24 July, 07:34
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y-2x=1
3x-4y=1
y=1+2x
3x-4y=1
y=1+2x
3x-4 (1+2x) = 1
y=1+2x
3x-4-8x=1
y=1+2x
-5x-4=1
y=1+2x
-5x=1+4
y=1+2x
-5x=5
y=1+2x
x=-1
y=1+2 * (-1)
x=-1
y=1 + (-2)
x=-1
y=-1
x=-1
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