a chemist has two solutions of h2so he has one 40% concentration the other has 25% concentration how many liters of each solution must be mixed to obtain 96 L of a 37% solution

Qty % = Qty (%)

Solution 1: x. 40.40 (x)

Solution 2: 96 - x. 25.25 (96 - x)

Mixture: 96.37.40x +.25 (96 - x)

96 (.37) =.40x +.25 (96 - x)

35.52 =.40x + 24 -.25x

35.52 =.15x + 24

11.52 =.15x

76.8 = x

Solution 2: 96 - x = 96 - 76.8 = 19.2

Answer: 76.8 L of 40% solution, 19.2 L of 25% solution