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Katrina Leon
Mathematics
29 October, 11:09
How do you solve y^2=12y-36
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Rachel Zamora
29 October, 11:31
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We move all the expressions to one side. We would have:
y^2-12y+36=0
(y-6) (y-6) = 0 (Because when you multiply (y-6) (y-6) you get y^2-12y+36)
The only possible answer would be y=6
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