A train left a station at noon going at 40 mph. A second train left at 3 p. m. going in the same direction at 60 mph. At what time will the second train catch up with the first?

Question

Adriana Mckee

Mathematics

16 December, 21:57

A train left a station at noon going at 40 mph. A second train left at 3 p. m. going in the same direction at 60 mph. At what time will the second train catch up with the first?

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Answers (2)

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Barnaby · Answer 1

I think at 6pm he will get caught up, correct my calculations if im wrong.

Landin Levy · Answer 2

Noon to 3 that is a 3 hour diffrence 40 miles in an hour and 60 miles in an hour that will be a 20mph difference.

The distance that was traveled by the first train is 40

The distance by the second is 60 it started 3 hours late

40t=60

40t=60180

20t=180

t=9

The second train will catch up at 9.00 pm