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9 June, 02:24

Determine the discriminant for the quadratic equation 0=-2x^2+3 Based on the discriminant value, how many real number

solutions does the equation have?

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Answers (1)
  1. 9 June, 02:46
    0
    This problem has two number solutions. The solutions are x = ±√ 1.500 = ± 1.22474.

    Step-by step explanation:

    Step 1:

    Equation at the end of step 1:

    0 - ((0 - 2x2) + 3) = 0

    Step 2:

    Trying to factor as a Difference of Squares:

    2.1 Factoring: 2x2-3

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : 2 is not a square!

    Ruling : Binomial can not be factored as the

    difference of two perfect squares

    Equation at the end of step 2:

    2x2 - 3 = 0

    Step 3:

    Solving a Single Variable Equation:

    3.1 Solve : 2x2-3 = 0

    Add 3 to both sides of the equation:

    2x2 = 3

    Divide both sides of the equation by 2:

    x2 = 3/2 = 1.500

    When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

    x = ± √ 3/2

    The equation has two real solutions

    These solutions are x = ±√ 1.500 = ± 1.22474
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