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13 October, 05:09

Is it possible to solve a quadratic equation that is not factorable over the set of integers? Explain.

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  1. 13 October, 06:50
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    YES, it is possible to solve a quadratic equation that is not factorable over the set of integers.

    Step-by-step explanation:

    A quadratic equation is a condition of the second degree, which means it contains no less than one term that is squared. The standard frame is

    ax² + bx + c = 0

    with a, b, and c being constants or numerical coefficients, and x is an obscure variable.

    The quadratic equation includes just a single obscure, it is designated "univariate". Specifically, it is a second-degree polynomial condition, since the best power is two.

    Whenever factorization fails you can use:

    a) completing the square method

    b) quadratic formula

    to solve the quadratic equation.

    The answers can lead you to the complex numbers but there is always a solution.
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