Ask Question
9 January, 13:53

A parked car dripping transmission fluid is creating a circular puddle whose area (in square inches) is Aequalspir2 where r is the radius of the circle in inches. Find the rate at which the area of the puddle is increasing at the instant when the radius is 9 inches and increasing at a rate of 3 inches per minute.

+3
Answers (1)
  1. 9 January, 14:21
    0
    dA/dt = 169,56 in²/min

    Step-by-step explanation:

    We have a circular puddle and its area is:

    A = π*r² (1) r is the radius of the circular puddle

    Differentiating on both sides of the equation we get:

    dA/dt = π*2*r*dr/dt (1)

    In that expression we know

    r = 9 inches and dr/dt = 3 in/min. Therefore plugging these values in equation (1)

    dA/dt = π*2*9*3

    dA/dt = 169,56 in²/min
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A parked car dripping transmission fluid is creating a circular puddle whose area (in square inches) is Aequalspir2 where r is the radius ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers