Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 55°, a = 12, b = 14

The way you'd set it up would be sin55º/12=sinB/14 (you could also flip the equation so that 12/sin55º=14/sinB, you'll get the same answer either way). Multiply out so that its 14•sin55º=12•sinB, or 11.47=12•sinB. Divide both sides by 12 so that it looks like. 96=sinB, then take arcsine of both sides (arcsin = x=sin^-1 theta+360n or x=180 - (sin^-1 theta) + 360n), which should give you about 72.88º and 107.12º.