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henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. he will get a second turn if he rolls a sum that is an even number less than 10. what are henry's chances of getting a second turn when he rolls the number cubes

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  1. 6 April, 22:10
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    Henry has 13 chances to get a second turn.

    Step-by-step explanation:

    When two number cubes numbered from 1 to 6 are rolled, the number of possible outcomes are 36.

    The 36 possible outcomes are as follows:

    (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

    (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

    (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

    (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

    (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

    (6,1), (6,2), (6,3), (6,4), (6,5), (6,6).

    It is given that, Henry gets the second turn if he rolls a sum that is an even number less than 10.

    Therefore, the even numbers less than 10 are {2,4,6,8}.

    Check for the sum of outcomes that gives the result of even number less than 10.

    Sum of (1,1) (1,3) (1,5) gives 2,4,6 which are even numbers less than 10 ⇒ 3 chances. Sum of (2,2) (2,4) (2,6) gives 4,6,8 which are even numbers less than 10 ⇒ 3 chances. Sum of (3,3) (3,5) gives 6 and 8 which are even numbers less than 10 ⇒ 2 chances. Sum of (4,2) (4,4) gives 6 and 8 which are even numbers less than 10 ⇒ 2 chances. Sum of (5,1) (5,3) gives 6 and 8 which are even numbers less than 10 ⇒ 2 chances. Sum of (6,2) gives 8 which is a even number less than 10 ⇒ 1 chance.

    The total number of chances to get second turn = 3+3+2+2+2+1 = 13 chances.

    Therefore, Henry has 13 chances to get a second turn.
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