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13 March, 07:59

How do you solve 8/11 (n-10) = 64

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  1. 13 March, 08:13
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    n = 98

    Step-by-step explanation:

    8/11 x (n - 10) = 64

    multiply both sides of the equation by 11/8

    11/8 x 8/11 x (n-10) = 11/8 x 64

    reduce the numbers with greatest common divisor 11

    1/8 x 8 (n-10) = 11/8 x 64

    n - 10 = 11 x 8

    multiply the numbers

    n - 10 = 88

    so then you add the numbers

    n = 88 + 10

    n = 98
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