The perimeter of a soccer field is 304 yards. The area is 5,520 square yards. What are the dimensions of the field?

Area=legnth times width

perimiter=legnth+legnth+width+width

perimiter=2 (legnth+width)

so

304=p=2 (legnth+width

5520=area=legnth times width

so we have

304=2 (l+w) and

5520=lw

304=2 (l+w)

divide by 2 to simplify

152=l+w

subtract w

152-w=l

subsitute 152-w for l

5520=lw

5520 = (152-w) (w)

distribute

5520=152w-w^2

subtract 152w from both sides

5520-152w=-w^2

add w^2 to both sides

w^2-152w+5520=0

factor the left side

(w-60) (w-92) = 0

set each to zero

w-60=0

w=60

w-92=0

w=92

w=92 or 60

dimentions are

60 yd by 92 yd