the length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimeter of the rectangle is 68 feet, what are the dimension (the length and width) of the rectangle?

Question

Dominguez

Mathematics

21 August, 05:17

the length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimeter of the rectangle is 68 feet, what are the dimension (the length and width) of the rectangle?

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Lance · Answer 1

Represent the length and width by L and W. Then L = W + 4.

Using the perimeter formula: P = 2L + 2W = 68 ft = 2W) + 2 (W+4).

Solve for W: 68 = 2W + 2W + 8, or 4W = 60. Thus, W = 15 and L = 19.

The dimensions of the rectangle are 15 by 19 feet.