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Mathematics
5 March, 09:16
Find the vertex of this parabola y=-x^2+6-8
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Kendrick Shields
5 March, 09:25
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Hello,
Your equation has a mistake: it is y=-x²+6x-8.
y=-x²+6x-8
= - (x²-6x) - 8
= - (x²-6x+9-9) - 8
= - (x-3) ²+9-8
= - (x-3) ²+1
Vertex is (3,1)
An other way more speedy:
y=-x²+6x-8
y'=-2x+6 = 0==>x=3 and y=-3²+6*3-8=1
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