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12 September, 17:27

If you were going to use the quadratic formula to solve the following equation and b=15, what number would you use as the value for the variable 'a'?

-15x+22=12x^2

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  1. 12 September, 17:47
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    You would use a = 12

    Step-by-step explanation:

    The b value is the coefficient that is in front of the x term, that does not have an exponent of 2. It's simply the x term (not the x^2 term)

    We're told that b = 15 is used, but we see that - 15 is in front of the x term. To fix this contradiction, add 15x to both sides so that you move the x term to the right side

    -15x+22 = 12x^2

    -15x+22+15x = 12x^2+15x

    22 = 12x^2+15x

    Now subtract 22 from both sides to move that term over as well

    22-22 = 12x^2 + 15x - 22

    0 = 12x^2 + 15x - 22

    12x^2 + 15x - 22 = 0

    12x^2 + 15x + (-22) = 0

    The last equation is in the form ax^2 + bx + c = 0 with

    a = 12, b = 15, c = - 22
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