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30 January, 21:23

There are three consecutive numbers such that twice the first is 20 more than the second. find the numbers? Show your solution.

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  1. 30 January, 21:53
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    Answering from phone so this will be a bit messy. a b=a+1 c=b+1=a+2 2a=b+20 Therefore: 2a=a+1+20 a=21, b=22, c=23
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