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17 April, 07:00

Two planes leave an airport at the same time, one flying east, the other flying west. The eastbound plane travels 20 mph slower. They are 1600 mi apart after 2 hr. Find the speed of each plane.

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  1. 17 April, 07:10
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    Let the speed of faster plane be x miles/hour

    so,

    the speed of the other plane will be (x-20) Mph

    The distance covered by both of them in 2hours:

    Faster plane = 2 h * (x) Mph = 2x miles

    Slower plane = 2 (x-20) miles

    Now according to question,

    2x + 2 (x-20) = 1600

    2x + 2x - 40 = 1600

    4x = 1560

    x = 440miles

    Therefore the speed of faster plane = 400Mph

    and the slower one will be (400-20) Mph = 380Mph
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