Using a pair of dice, what is the probability of throwing a sum of nice twice in a row?

1/16

Step-by-step explanation:

+ Dice2

Dice1 1 2 3 4 5 6

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

Probability = number of desired outcome / total number of outcome

= 4 / 36

= 1/9

The probability of rolling a 9 the first time is therefore = 1/4

The probability of rolling a 9 twice in a row is just the product of the probability for two independent rolls each producing a 9.

That is, 1/4 * 1/4 = 1/16 = 0.0625.