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28 March, 20:31

David is standing 500 feet away from the base of the cell tower the angle of elevation from his eyes to the top of the tower 78° is David eyes are 6 feet above the ground how tall is the tower

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  1. 28 March, 20:46
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    Answer: the tower is 2358.3 feet tall

    Step-by-step explanation:

    A right angle triangle is formed between the tower, the angle of elevation of David's eyes and his distance from the tower.

    Since the angle of elevation from his eyes to the top of the tower 78°, his distance from the tower represents the adjacent side of the right and triangle and the height of the tower represents the opposite side of the right angle triangle.

    To determine the height of the tower, h we would apply

    the tangent trigonometric ratio.

    Tan θ, = opposite side/adjacent side. Therefore,

    Tan 78 = h/500

    h = 500tan78 = 500 * 4.7046

    h = 2352.3

    The total height of the tower would be 2352.3 + 6 = 2358.3 feet
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