Mr. Jameson is walking toward his nine-story hotel and stops to look up to the top of the building. The angle of elevation to the top of the hotel is 55°. If the height of the hotel is 108 feet, about how far away is Mr. Jameson from the hotel?

Question

Misael

Mathematics

22 October, 03:33

Mr. Jameson is walking toward his nine-story hotel and stops to look up to the top of the building. The angle of elevation to the top of the hotel is 55°. If the height of the hotel is 108 feet, about how far away is Mr. Jameson from the hotel?

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Answers (1)

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Hugh Palmer · Answer 1

The side of the hotel is opposite to the angle.

The distance between Mr. Jameson and the hotel is adjacent to the measured angle.

Tan = sin/cos = adjacent / opposite

Tan (55) = 108/x

x = 75.6ft