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17 May, 03:38

Determine b, given that A = 63°, C = 49°, and c = 3.

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  1. 17 May, 03:57
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    A=63°

    C=49°

    c=3

    b=?

    Solution:

    A+B+C=180°

    63°+B+49°=180°

    B+112°=180°

    Solving for B:

    B+112°-112°=180°-112°

    B=68°

    Using Law of Sines:

    b/sin B = c/sin C

    b/sin 68°=3/sin 49°

    Solving for b:

    sin 68° (b/sin 68°) = sin 68° (3/sin 49°)

    b=3 sin 68°/sin 49°

    sin 68°=0.927183855

    sin 49°=0.754709580

    b=3 (0.927183855) / 0.754709580

    b=3.685591966

    b=3.6856
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